- 學位論文
反應燒結法製備熱電陶瓷 CuAl1-xMxO2 (M = Ca, Fe) 之研究
Preparation of CuAl1-xMxO2 (M=Ca, Fe) thermoelectric ceramics via reaction-sintering process
摘要
本研究以反應燒結法製備CuAl1-xMxO2 (M = Ca, Fe)熱電陶瓷，在製造陶瓷體的過程中直接將原料粉末混合球磨、烘乾、壓模成型後，不經任何煆燒步驟而直接進行燒結。從所有樣本之XRD分析結果，我們可以觀察到使用反應燒結法能夠得到與CuAlO2相同結構之CuAl1-xMxO2陶瓷，其中CuAlO2及CuAl0.9Fe0.1O2皆為單一相。在密度分析中，可以發現Fe的添加，對整體密度的提升以及燒結溫度的下降相當有幫助，其中CuAl0.9Fe0.1O2在1200oC燒結4小時可以得到最佳密度4.734 g/cm3，另外CuAl0.8Fe0.2O2在1150oC燒結6小時更可以得到4.906 g/cm3的最大密度。在100-600oC，CuAl0.9Fe0.1O2與CuAl0.9Ca0.1O2陶瓷具有與CuAlO2相當之Seebeck係數300-500 μVK-1。CuAl0.9Fe0.1O2陶瓷具有高於CuAlO2導電率及功率因子，在600oC時有最大導電率3.143Ω-1cm-1及最佳功率因子5.487×10-5 Wm-1K-2。
並列摘要
In this study, preparation of thermoelectric ceramics CuAl1-xMxO2 (M=Ca, Fe) via reaction-sintering process was investigated. Without any calcination involved, the mixture of raw materials was pressed and sintered directly. From the XRD results, CuAl1-xMxO2 ceramics with the same crystal structure of CuAlO2 could be obtained. Among all compositions, single-phase CuAlO2 and CuAl0.9Fe0.1O2 pellets were obtained. The addition of Fe2O3 increased the density and lowered the sintering temperature obviously. A density 4.734 g/cm3 was found in CuAl0.9Fe0.1O2 sintered at 1200oC for 4 hours. CuAl0.8Fe0.2O2 with a density 4.906 g/cm3 was obtained after sintering at 1150oC for 6 hours. CuAl0.9Fe0.1O2 and CuAl0.9Ca0.1O2 were found to exhibit similar Seebeck coefficient as CuAlO2, 300-500 μVK-1 at 100-600oC. The electrical conductivity and power factor of CuAl0.9Fe0.1O2 were higher than CuAlO2. CuAl0.9Fe0.1O2 exhibited electrical conductivity 3.143Ω-1cm-1 and power factor 5.487 × 10-5 Wm-1K-2 at 600oC.